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2022 AMC 10B Problem 5

Problem 5 of 25EasierAlgebra

What is the value of (1+13)(1+15)(1+17)(1132)(1152)(1172)?\frac{\left(1+\frac{1}{3}\right)\left(1+\frac15\right)\left(1+\frac17\right)}{\sqrt{\left(1-\frac{1}{3^2}\right)\left(1-\frac{1}{5^2}\right)\left(1-\frac{1}{7^2}\right)}}?

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Solution

Let the given positive expression be E.E. Squaring it and using 11p2=(11p)(1+1p)1-\frac{1}{p^2}=(1-\frac{1}{p})(1+\frac{1}{p}) gives E2=p{3,5,7}1+1p11p=426486=4. \begin{aligned} E^2&=\prod_{p\in\{3,5,7\}}\frac{1+\frac{1}{p}}{1-\frac{1}{p}}\\ &=\frac42\cdot\frac64\cdot\frac86=4. \end{aligned} Hence E=2.E=2. Thus, the answer is B .

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Concepts: difference of squares · radical

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.