2022 AMC 10B Problem 2

Since $ABCD$ is a rhombus, $$AB=AD=AP+PD=5.$$ Right triangle $ABP$ then gives $$\begin{aligned}BP&=\sqrt{AB^2-AP^2}\\&=\sqrt{25-9}=4.\end{aligned}$$ Thus the rhombus has base $AD=5$ and height $BP=4,$ so its area is $5\cdot4=20.$ Thus, the answer is D .