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2023 AMC 10A Problem 5

Problem 5 of 25EasierNumber Theory

How many digits are in the base-ten representation of 85⋅510⋅155?8^5 \cdot 5^{10} \cdot 15^5?

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Solution

Factor everything into primes. 85⋅510⋅1558^5 \cdot 5^{10} \cdot 15^5 =215⋅510⋅35⋅55= 2^{15} \cdot 5^{10} \cdot 3^5 \cdot 5^5 =215⋅515⋅35= 2^{15} \cdot 5^{15} \cdot 3^5 =1015⋅243.= 10^{15} \cdot 243. That’s 243243 followed by 1515 zeros, so it has 3+15=183 + 15 = 18 digits. Thus, E is the correct answer.
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Tagged: prime factorization · digits

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