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2023 AMC 10A Problem 8

Problem 8 of 25EasierAlgebraGeometry

Barb the baker creates a new temperature system for baking bread, Breadus, which is linearly based on Fahrenheit. Bread rises at 110 F,110\text{ F}^{\circ}, which is 00 on the Breadus scale. Bread bakes at 350 F,350\text{ F}^{\circ}, which is 100100 on the Breadus scale. Bread is done when its internal temperature is 200 F.200\text{ F}^{\circ}. What is this temperature on the Breadus scale?

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Solution

The Breadus reading is linear in Fahrenheit through (110,0)(110, 0) and (350,100),(350, 100), so B=100350110(F110)B = \frac{100}{350 - 110}(F - 110) =512(F110).= \frac{5}{12}(F - 110). Plug in F=200:F = 200: B=51290=37.5.B = \frac{5}{12} \cdot 90 = 37.5. Therefore, the answer is D.

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Concepts: linear equation · slope

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.