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2023 AMC 10A Problem 9

Problem 9 of 25EasierNumber Theory

A digital display shows the current date as an 88-digit integer consisting of a 44-digit year, followed by a 22-digit month, followed by a 22-digit date within the month. For example, Arbor Day this year is displayed as 20230428.20230428. For how many dates in 20232023 will each digit appear an even number of times in the 88-digit display for that date?

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Solution

The year 20232023 already gives two 22s (even), one 00, and one 33. So to make every digit occur an even number of times, the four digits of MMMM and DDDD must supply one more 00, one more 33, and two equal digits, while keeping the number of 22s even. Checking the legal dates gives 01/13,01/13, 01/31,01/31, 02/23,02/23, 03/11,03/11, 03/22,03/22, 10/13,10/13, 10/31,10/31, 11/03,11/03, and 11/30,11/30, exactly 99 dates. Thus, E is the correct answer.

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Concepts: digits · parity · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.