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2000 AMC 12 Problem 13

Problem 13 of 25IntermediateAlgebra

One morning each member of Angela’s family drank an 88-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?

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Solution

Measure amounts in 88-ounce cups, so Angela’s cup holds cc coffee and mm milk with c+m=1.c + m = 1. Since Angela drank a sixth of the coffee, the total coffee is 6c6c; since she drank a quarter of the milk, the total milk is 4m.4m. The number of people equals the total number of cups, 6c+4m=6c+4(1c)=4+2c. \begin{aligned} 6c + 4m &= 6c + 4(1 - c) \\ &= 4 + 2c. \end{aligned} This is an integer only when 2c2c is an integer, and since 0<c<10 \lt c \lt 1 this forces c=12,c = \tfrac12, giving 4+1=54 + 1 = 5 people. Thus, the correct answer is C.

More practice

Concepts: fraction · linear equation · bounding to limit cases

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