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2000 AMC 12 Problem 25

Problem 25 of 25HarderCounting & Probability

Eight congruent equilateral triangles, each of a different color, are used to construct a regular octahedron. How many distinguishable ways are there to construct the octahedron? (Two colored octahedrons are distinguishable if neither can be rotated to look just like the other.)

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Solution

There are 8!8! ways to assign the eight distinct colors to the eight faces. Two assignments give the same octahedron exactly when one is a rotation of the other. The rotation group of a regular octahedron has 2424 elements. Because all eight colors are different, no nontrivial rotation fixes a coloring, so each distinguishable octahedron corresponds to exactly 2424 assignments. Therefore the number of distinguishable octahedrons is 8!24=4032024=1680. \frac{8!}{24} = \frac{40320}{24} = 1680. Thus, the correct answer is E.

More practice

Concepts: Burnside’s Lemma · permutations · symmetry

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.