2000 AMC 12 Problem 5Problem 5 of 25·Easier·AlgebraIf ∣x−2∣=p,|x - 2| = p,∣x−2∣=p, where x<2,x \lt 2,x<2, then what is x−p?x - p?x−p?Answer choicesA−2-2−21B2222C2−2p2 - 2p2−2p3D2p−22p - 22p−24E∣2p−2∣|2p - 2|∣2p−2∣5Submit answerStuck? Show hintsShow solutionSolutionSince x<2,x \lt 2,x<2, we have ∣x−2∣=2−x=p,|x - 2| = 2 - x = p,∣x−2∣=2−x=p, so x=2−p.x = 2 - p.x=2−p. Then x−p=(2−p)−p=2−2p. x - p = (2 - p) - p = 2 - 2p. x−p=(2−p)−p=2−2p. Thus, the correct answer is C.AoPS wikiCopy problemTagged: absolute value