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2003 AMC 12A Problem 21

Problem 21 of 25HarderAlgebra

The graph of the polynomial P(x)=x5+ax4+bx3+cx2+dx+e \begin{aligned} &P(x) = x^5 + ax^4 + bx^3 \\ &\quad {}+ cx^2 + dx + e \end{aligned} has five distinct xx-intercepts, one of which is at (0,0).(0, 0). Which of the following coefficients cannot be zero?

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Solution

Since (0,0)(0,0) is an intercept, P(0)=e=0,P(0)=e=0, so P(x)P(x) =x(x4+ax3+bx2+cx+d).=x\left(x^4+ax^3+bx^2+cx+d\right). The four remaining intercepts are nonzero and distinct, and dd equals their product, which is therefore nonzero. Any of a,b,ca,b,c can be zero for suitable choices of those roots, but d0.d\neq0. Thus, the correct answer is D.

More practice

Concepts: Vieta’s Formulas · polynomial

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.