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2004 AMC 12A Problem 6

Problem 6 of 25EasierAlgebra

Let U=220042005,U = 2 \cdot 2004^{2005}, V=20042005,V = 2004^{2005}, W=200320042004,W = 2003 \cdot 2004^{2004}, X=220042004,X = 2 \cdot 2004^{2004}, Y=20042004Y = 2004^{2004} and Z=20042003.Z = 2004^{2003}. Which of the following is largest?

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Solution

Compute each difference by factoring: UV=20042005,U - V = 2004^{2005}, VW=20042004,V - W = 2004^{2004}, WX=200120042004,W - X = 2001 \cdot 2004^{2004}, XY=20042004,X - Y = 2004^{2004}, and YZ=200320042003.Y - Z = 2003 \cdot 2004^{2003}. Since 20042005=2004200420042004^{2005} = 2004 \cdot 2004^{2004} exceeds each of the others, none of which reaches 20042005,2004^{2005}, the difference UVU - V is the largest. Thus, the correct answer is A.

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Concepts: factoring · exponent

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