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2008 AMC 12B Problem 10

Problem 10 of 25EasierAlgebra

Bricklayer Brenda would take 99 hours to build a chimney alone, and bricklayer Brandon would take 1010 hours to build it alone. When they work together, they talk a lot, and their combined output is decreased by 1010 bricks per hour. Working together, they build the chimney in 55 hours. How many bricks are in the chimney?

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Solution

Let nn be the number of bricks. Alone, Brenda lays n9\tfrac{n}{9} bricks per hour and Brandon lays n10.\tfrac{n}{10}. Together, their rate is n9+n1010.\tfrac{n}{9} + \tfrac{n}{10} - 10. Working for 55 hours completes the chimney: 5(n9+n1010)=n. 5\left(\tfrac{n}{9} + \tfrac{n}{10} - 10\right) = n. Expanding, 5n9+5n1050=n,\tfrac{5n}{9} + \tfrac{5n}{10} - 50 = n, so 95n90n=50,\tfrac{95n}{90} - n = 50, giving 5n90=50.\tfrac{5n}{90} = 50. Hence n=900.n = 900. Thus, the correct answer is B.

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Concepts: rate · linear equation

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