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2008 AMC 12B Problem 14

Problem 14 of 25IntermediateAlgebraGeometry

A circle has a radius of log10(a2)\log_{10}(a^2) and a circumference of log10(b4).\log_{10}(b^4). What is logab?\log_a b?

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Solution

The circumference is 2π2\pi times the radius, so log10(b4)=2πlog10(a2). \log_{10}(b^4) = 2\pi \log_{10}(a^2). Rewriting, 4log10b=4πlog10a,4\log_{10} b = 4\pi \log_{10} a, hence log10b=πlog10a.\log_{10} b = \pi \log_{10} a. Therefore logab=log10blog10a=π.\log_a b = \dfrac{\log_{10} b}{\log_{10} a} = \pi. Thus, the correct answer is C.

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Concepts: logarithm · circumference

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.