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2008 AMC 12B Problem 18

Problem 18 of 25IntermediateGeometry

A pyramid has a square base ABCDABCD and vertex E.E. The area of square ABCDABCD is 196,196, and the areas of ABE\triangle ABE and CDE\triangle CDE are 105105 and 91,91, respectively. What is the volume of the pyramid?

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Solution

The square has side 196=14.\sqrt{196} = 14. Let FF and GG be the feet of the perpendiculars from EE to ABAB and CD.CD. Then FG=14,FG = 14, EF=210514=15,EF = \tfrac{2 \cdot 105}{14} = 15, and EG=29114=13.EG = \tfrac{2 \cdot 91}{14} = 13. Triangle EFGEFG lies in a plane perpendicular to the base, so its altitude to FGFG is the pyramid’s height. By Heron’s formula with s=21,s = 21, its area is 21687=84,\sqrt{21 \cdot 6 \cdot 8 \cdot 7} = 84, so the altitude to FGFG is 28414=12.\tfrac{2 \cdot 84}{14} = 12. The volume is 1319612=784.\tfrac13 \cdot 196 \cdot 12 = 784. Thus, the correct answer is E.

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Concepts: pyramid · volume · Heron’s Formula

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.