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2008 AMC 12B Problem 6

Problem 6 of 25EasierAlgebraNumber Theory

Postman Pete has a pedometer to count his steps. The pedometer records up to 9999999999 steps, then flips over to 0000000000 on the next step. Pete plans to determine his mileage for a year. On January 11 Pete sets the pedometer to 00000.00000. During the year, the pedometer flips from 9999999999 to 0000000000 forty-four times. On December 3131 the pedometer reads 50000.50000. Pete takes 18001800 steps per mile. Which of the following is closest to the number of miles Pete walked during the year?

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Solution

Each flip counts 100000100000 steps, so the year’s steps total 44100000+50000=4,450,000. \begin{aligned} &44 \cdot 100000 \\ &\quad {}+ 50000 = 4{,}450{,}000. \end{aligned} At 18001800 steps per mile, the mileage is 4,450,00018002472,\dfrac{4{,}450{,}000}{1800} \approx 2472, which is closest to 2500.2500. Thus, the correct answer is A.

More practice

Concepts: place value · estimation · unit conversion

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.