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2008 AMC 12B Problem 2

Problem 2 of 25EasierAlgebra

A 4×44 \times 4 block of calendar dates is shown. The order of the numbers in the second row is to be reversed. Then the order of the numbers in the fourth row is to be reversed. Finally, the numbers on each diagonal are to be added. What will be the positive difference between the two diagonal sums?

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Solution

Reversing the second and fourth rows gives the array with rows 1234,1\,2\,3\,4, 111098,11\,10\,9\,8, 15161718,15\,16\,17\,18, and 25242322.25\,24\,23\,22. The main diagonal sums to 1+10+17+22=50,1 + 10 + 17 + 22 = 50, and the other diagonal sums to 4+9+16+25=54.4 + 9 + 16 + 25 = 54. The positive difference is 5450=4.54 - 50 = 4. Thus, the correct answer is B.

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Concepts: arithmetic sequence · pattern recognition

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