Skip to main content

2008 AMC 12B Problem 8

Problem 8 of 25EasierArithmetic

Points BB and CC lie on AD‾.\overline{AD}. The length of AB‾\overline{AB} is 44 times the length of BD‾,\overline{BD}, and the length of AC‾\overline{AC} is 99 times the length of CD‾.\overline{CD}. The length of BC‾\overline{BC} is what fraction of the length of AD‾?\overline{AD}?

Answer choices

Show solution

Solution

Since AB=4 BDAB = 4\,BD and AB+BD=AD,AB + BD = AD, we have 5 BD=AD,5\,BD = AD, so BD=15AD.BD = \tfrac{1}{5}AD. Likewise AC=9 CDAC = 9\,CD with AC+CD=ADAC + CD = AD gives CD=110AD.CD = \tfrac{1}{10}AD. Because BB and CC both measure from A,A,   BC=BD−CD\;BC = BD - CD =15AD−110AD= \tfrac{1}{5}AD - \tfrac{1}{10}AD =110AD.= \tfrac{1}{10}AD. Thus, the correct answer is C.
AoPS wiki

Tagged: ratio and proportion

More practice