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2011 AMC 12B Problem 6

Problem 6 of 25EasierGeometry

Two tangents to a circle are drawn from a point A.A. The points of contact BB and CC divide the circle into arcs with lengths in the ratio 2:3.2:3. What is the degree measure of BAC?\angle BAC?

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Solution

Let OO be the center. The arcs measure 2x2x and 3x3x with 2x+3x=360,2x+3x=360^\circ, so x=72x=72^\circ and the minor arc BCBC gives central angle BOC=144.\angle BOC=144^\circ. The radii to BB and CC are perpendicular to the tangents, so ABO=ACO=90.\angle ABO=\angle ACO=90^\circ. In quadrilateral ABOC,ABOC, BAC=3601449090=36. \begin{gathered} \angle BAC=360^\circ-144^\circ-90^\circ \\ {}-90^\circ=36^\circ. \end{gathered} Thus, the correct answer is C.

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Concepts: tangent line · arc · angle chasing

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.