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2011 AMC 12B Problem 9

Problem 9 of 25EasierCounting & Probability

Two real numbers are selected independently at random from the interval [20,10].[-20, 10]. What is the probability that the product of those numbers is greater than zero?

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Solution

The interval has length 30,30, with 2020 of it negative and 1010 of it positive. So each number is positive with probability 13\dfrac13 and negative with probability 23.\dfrac23. The product is positive when both are positive or both are negative: (13)2+(23)2=19+49=59. \left(\dfrac13\right)^2+\left(\dfrac23\right)^2=\dfrac19+\dfrac49=\dfrac59. Thus, the correct answer is D.

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Concepts: geometric probability · independent events

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.