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2017 AMC 12A Problem 17

Problem 17 of 25IntermediateAlgebra

There are 2424 different complex numbers zz such that z24=1.z^{24}=1. For how many of these is z6z^6 a real number?

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Solution

The 2424 solutions are the 2424th roots of unity, z=eπik12z=e^{\frac{\pi i k}{12}} for k=0,1,,23.k=0,1,\ldots,23. Then z6=eπik2=coskπ2+isinkπ2,z^6=e^{\frac{\pi i k}{2}}=\cos\dfrac{k\pi}{2}+i\sin\dfrac{k\pi}{2}, which is real exactly when sinkπ2=0,\sin\dfrac{k\pi}{2}=0, i.e. when kk is even. There are 1212 even values of kk in the range. Thus, the correct answer is D.

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Concepts: roots of unity · complex number

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.