2020 AMC 12B Problem 2

Using the difference of squares, $100^2 - 7^2 = (100 - 7)(100 + 7)$ and $70^2 - 11^2 = (70 - 11)(70 + 11).$ The expression becomes $$\begin{aligned} &\frac{(100 - 7)(100 + 7)}{(70 - 11)(70 + 11)} \\ &\quad {}\cdot \frac{(70 - 11)(70 + 11)}{(100 - 7)(100 + 7)} = 1. \end{aligned}$$ Thus, the correct answer is A.