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2021 Fall AMC 12B Problem 12

Problem 12 of 25IntermediateNumber Theory

For nn a positive integer, let f(n)f(n) be the quotient obtained when the sum of all positive divisors of nn is divided by n.n. For example, f(14)=(1+2+7+14)÷14=127. \begin{aligned} f(14) &= (1 + 2 + 7 + 14) \div 14 \\ &= \dfrac{12}{7}. \end{aligned} What is f(768)f(384)?f(768) - f(384)?

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Solution

Since 768=283,768 = 2^8 \cdot 3, its divisor sum is (291)(1+3)(2^9 - 1)(1 + 3) =5114=2044,= 511 \cdot 4 = 2044, so f(768)=2044768=511192.f(768) = \dfrac{2044}{768} = \dfrac{511}{192}. Since 384=273,384 = 2^7 \cdot 3, its divisor sum is (281)(1+3)(2^8 - 1)(1 + 3) =2554=1020,= 255 \cdot 4 = 1020, so f(384)=1020384=510192.f(384) = \dfrac{1020}{384} = \dfrac{510}{192}. The difference is 511510192=1192.\dfrac{511 - 510}{192} = \dfrac{1}{192}. Thus, the correct answer is B.

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Concepts: sum of factors · prime factorization

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