2021 Fall AMC 12B Problem 2

The outer triangle has vertices $(1, 0),$ $(3, 5),$ and $(5, 0),$ giving base $4$ and height $5,$ so its area is $\tfrac12 \cdot 4 \cdot 5 = 10.$ Removed from it is the triangle with vertices $(1, 0),$ $(3, 2),$ and $(5, 0),$ which has base $4$ and height $2,$ so area $\tfrac12 \cdot 4 \cdot 2 = 4.$ The shaded area is $10 - 4 = 6.$ Thus, the correct answer is B.