2010/11 AHSMC Part 1 Problem 1Problem 1 of 16The number of positive integers nnn such that the number 4n4n4n has exactly two digits isAnswer choicesA2121211B2222222C2323233D2424244E2525255Submit answerShow solutionSolutionSince 10≤4n≤9910 \le 4n \le 9910≤4n≤99, 3≤n≤243 \le n \le 243≤n≤24. Hence there are 24−3+1=2224 - 3 + 1 = 2224−3+1=22 such values. The answer is (B).University of AlbertaCopy problem