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2010/11 AHSMC Part 1

All 16 problems. Take it as a timed test — 1:20:00 on the clock, scored the way the AMC is — or read through the problems and open any of them for its worked solution.

16 problems · 6 points correct, 1.5 for blank, 0 for wrong

  1. The number of positive integers nn such that the number 4n4n has exactly two digits is

  2. A 4×64 \times 6 plot of land is divided into 1×11 \times 1 lots by fences parallel to the edges of the plot, with fences along the edges as well. The total length of fences is:

  3. The greatest common divisor and least common multiple of two positive integers are 11 and 1010 respectively. If neither of them is equal to 1010, their sum is equal to

  4. The number of pairs (x,y)(x, y) of non-negative integers such that 3x+2y=273x + 2y = 27 is

  5. In the sequence 1,2,3,4,6,7,8,9,…1, 2, 3, 4, 6, 7, 8, 9, \ldots, obtained by deleting the multiples of 55 from the sequence of the positive integers, the 20102010th term is

  6. Alice, Brian, Colin, Debra and Ethel are in a hotel. Their rooms are on floors 11, 22, 33, 2121 and 4040 respectively. In order to minimize the total number of floors they have to cover to get together, the floor on which the get-together should be is

  7. A square pigeon coop is divided by interior walls into 99 square pigeonholes in a 3×33 \times 3 configuration. Each of two pigeons chooses a pigeonhole at random, possibly the same one. The probability that they choose two holes on the opposite sides of an interior wall is

  8. The set of all values of the real number xx such that 1x≤−3≤x\frac{1}{x} \le -3 \le x is

  9. In the quadrilateral ABCDABCD, ABAB is parallel to DCDC, DC=2ABDC = 2AB, ∠ADC=30∘\angle ADC = 30^\circ and ∠BCD=50∘\angle BCD = 50^\circ. Let MM be the midpoint of CDCD. The measure of ∠AMB\angle AMB is

  10. We are constructing isosceles but non-equilateral triangles with positive areas and integral side lengths between 11 and 99 inclusive. The number of such triangles which are non-congruent is

  11. In each of the following numbers, the exponents are to be evaluated from top down. For instance, abc=a(bc)a^{b^c} = a^{(b^c)}. The largest one of these five numbers is

  12. A gold number is a positive integer which can be expressed in the form ab+a+bab + a + b, where aa and bb are positive integers. The number of gold numbers between 11 and 2020 inclusive is

  13. The edges DADA, DBDB and DCDC of a tetrahedron ABCDABCD are perpendicular to one another. If the length of DADA is 11 cm and the length of each of DBDB and DCDC is 22 cm, the radius, in cm, of the sphere passing through AA, BB, CC and DD is

  14. Let f(x)=x2f(x) = x^2 and g(x)=x4g(x) = x^4. We apply ff and gg alternatively to form f(x)=x2,g(f(x))=g(x2)=(x2)4=x8,f(g(f(x)))=f(x8)=(x8)2=x16, f(x) = x^2,\quad g(f(x)) = g(x^2) = (x^2)^4 = x^8,\quad f(g(f(x))) = f(x^8) = (x^8)^2 = x^{16}, and so on. After we have applied ff 5050 times and gg 4949 times, the answer is xnx^n where nn is

  15. Triangle ABCABC has area 11. XX, YY are points on the side ABAB and ZZ a point on the side ACAC such that XY=2AXXY = 2AX, XZXZ is parallel to YCYC and YZYZ is parallel to BCBC. The area of XYZXYZ is

  16. The number of integers nn for which n3−3n+2n^3 - 3n + 2 is divisible by 2n+12n + 1 is

0 of 16 answered. Each problem left blank still scores 1.5 points.