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2018/19 AHSMC Part 1

All 16 problems. Take it as a timed test — 1:20:00 on the clock, scored the way the AMC is — or read through the problems and open any of them for its worked solution.

16 problems · 6 points correct, 1.5 for blank, 0 for wrong

  1. The average of 11, aa and bb is equal to 2c2c. The average of 11, aa and cc is equal to 2b2b. The average of 11, bb and cc is equal to 2a2a. The average of aa, bb and cc is equal to

  2. Let a,b>0a, b > 0 and suppose the line y=b−axy = b - ax has an xx-intercept of 22. If the triangle enclosed by the lines x=0x = 0, y=0y = 0 and y=b−axy = b - ax has area equal to 44, the value of aa must be

  3. Let ff be a function such that f(x+13)=x2+x+3f\bigl(\dfrac{x+1}{3}\bigr) = x^2 + x + 3 for any real number xx. The sum of all real numbers aa such that f(a9)=10f\bigl(\dfrac{a}{9}\bigr) = 10 is

  4. A sequence is defined by a0=0a_0 = 0 and an+1=an−3an−2a_{n+1} = \dfrac{a_n - 3}{a_n - 2} for all integers n≥0n \ge 0. Then a2018a_{2018} is

  5. Pete has $x\$x in his pocket. If he buys two apples using his $x\$x he will have $3\$3 in change remaining. If he buys three bananas using his $x\$x he will have $2\$2 in change remaining. Similarly, if he buys four apples and one banana using his $x\$x he will also have $2\$2 in change remaining. What is the maximum number of bananas Pete can afford to buy?

  6. A student writes a multiple choice exam. The exam contains 1616 questions and the score is 55 points for a correct answer, 22 points for no answer and 00 points for an incorrect answer. Each student also receives 2020 bonus points. If a student scores 7878 points, how many questions were answered correctly?

  7. How many triplets (m,n,k)(m,n,k), of integers greater than one, exist such that (m!)⋅(n!)=(k!)(m!) \cdot (n!) = (k!)? (Notice that n!=1×2×3×⋯×nn! = 1 \times 2 \times 3 \times \cdots \times n.)

  8. The sum of all positive integers smaller than 126126 which are not divisible by 22 and not divisible by 33 is

  9. Let kk be a fixed positive real number. Suppose kx2≤10kx^2 \le 10 has exactly five positive integer solutions. The number of positive integer solutions to kx≤1kx \le 1 must be

  10. Consider polynomials p(x)p(x) of degree 55 with leading coefficient 11 such that p(−x)=−p(x)p(-x) = -p(x) for all real xx. If the roots of p(x)p(x) include −1-1 and 2\sqrt{2}, the value of p(2)p(2) is

  11. A set SS of five different real numbers is given. When each pair of these numbers are added, you get the ten sums −4,−3,−2,−1,0,1,4,5,6,8-4,-3,-2,-1,0,1,4,5,6,8. The ratio of the largest number in SS to the smallest number in SS is

  12. Let an=n2+2n+50a_n = n^2 + 2n + 50, n=1,2,…n = 1,2,\ldots. Let dnd_n be the largest positive integer that is a divisor of both ana_n and an+1a_{n+1}. The maximum value of dnd_n, n=1,2,…n = 1,2,\ldots is

  13. There are seven children belonging to three families. The first family has three children, and the other two families have two children each. In how many ways can these seven children be arranged in a circle so that no two children from the same family are next to each other? Notice that seating arrangements that differ by a rotation are considered the same.

  14. The positive integers from 11 to 999999 are written in a row (with no spaces) in increasing order: 12345⋯998999. 12345\cdots 998999. How many times does the sequence of characters “3131” occur?

  15. In triangle ABCABC, DD is a point on BCBC such that ∠BAD=30∘\angle BAD = 30^\circ and ∠DAC=15∘\angle DAC = 15^\circ. If AB=32AB = 3\sqrt{2} and AC=6AC = 6, the length of ADAD is

  16. Let k≥1k \ge 1 be an integer and nk=⌊2k+201820192k+1⌋n_k = \left\lfloor \dfrac{2^k + 20182019}{2^{k+1}} \right\rfloor where ⌊x⌋\lfloor x \rfloor denotes the largest integer less than or equal to xx. The value of the sum n1+n2+n3+⋯n_1 + n_2 + n_3 + \cdots is

0 of 16 answered. Each problem left blank still scores 1.5 points.