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2019/20 AHSMC Part 1 Problem 6

Problem 6 of 16

Consider a=21000a = 2^{1000}, b=3600b = 3^{600}, and c=10300c = 10^{300}. Which of the following is true?

Answer choices

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Solution

We have a=21000=(210)100=1024100a = 2^{1000} = (2^{10})^{100} = 1024^{100}, b=3600=(36)100=729100b = 3^{600} = (3^6)^{100} = 729^{100}, and c=10300=(103)100=1000100c = 10^{300} = (10^3)^{100} = 1000^{100}. We have 729<1000<1024729 < 1000 < 1024, and hence b<c<ab < c < a. The answer is (D).