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2012 AMC 10A Problem 11

Problem 11 of 25IntermediateGeometry

Externally tangent circles with centers at points AA and BB have radii of lengths 55 and 3,3, respectively. A line externally tangent to both circles intersects ray ABAB at point C.C. What is BC?BC?

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Solution

Let xx be BC.BC. Note that CEB\triangle CEB and CDA\triangle CDA are similar due to angle-angle (tangent lines are perpendicular to radii). Then x3=8+x5. \dfrac{x}{3} = \dfrac{8 + x}{5}. Cross-multiplying gives us 5x=24+3x 5x = 24 + 3x x=12. x = 12. Thus, D is the correct answer.

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Concepts: tangent circles · tangent line · similarity

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.