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2012 AMC 10A Problem 7

Problem 7 of 25EasierArithmetic

In a bag of marbles, 35\dfrac{3}{5} of the marbles are blue and the rest are red. If the number of red marbles is doubled and the number of blue marbles stays the same, what fraction of the marbles will be red?

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Solution

WLOG, let the number of marbles in the bag be 5.5. Since we only care about ratios, we can do this. Then there are 33 blue marbles and 22 red marbles. Doubling the red marbles gives us 44 of them. Then the fraction of red marbles is 44+3=47. \dfrac{4}{4 + 3} = \dfrac{4}{7}. Thus, C is the correct answer.
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Tagged: ratio and proportion · fraction

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