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2012 AMC 10A Problem 4

Problem 4 of 25EasierGeometryProblem-Solving Techniques

Let ∠ABC=24∘\angle ABC = 24^\circ and ∠ABD=20∘.\angle ABD = 20^\circ . What is the smallest possible degree measure for ∠CBD?\angle CBD?

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Solution

Note that both of the angles share the ray AB.AB. To minimize the desired degree, we want DD to be between AA and C.C. This would make ∠CBD=∠ABC−∠ABD=4∘. \begin{aligned} \angle CBD &= \angle ABC - \angle ABD \\ &= 4^{\circ}. \end{aligned} Thus, C is the correct answer.
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Tagged: angle chasing · optimization

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