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2014 AMC 10A Problem 10

Problem 10 of 25EasierAlgebra

Five positive consecutive integers starting with aa have average b.b. What is the average of 55 consecutive integers that start with b?b?

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Solution

Note that the average of 55 consecutive numbers starting with xx is 5x+1+2+3+45=x+2. \dfrac{5x + 1 + 2 + 3 + 4}{5} = x + 2. This means that the average of 55 consecutive integers starting with aa is a+2,a + 2, which we know is b.b. Furthermore, the average of 55 consecutive numbers starting with bb is b+2=a+4.b + 2 = a + 4. Thus, B is the correct answer.

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Concepts: arithmetic sequence · mean

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.