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2014 AMC 10A Problem 10

Problem 10 of 25EasierAlgebraProbability & Statistics

Five positive consecutive integers starting with aa have average b.b. What is the average of 55 consecutive integers that start with b?b?

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Solution

Note that the average of 55 consecutive numbers starting with xx is 5x+1+2+3+45=x+2. \dfrac{5x + 1 + 2 + 3 + 4}{5} = x + 2. This means that the average of 55 consecutive integers starting with aa is a+2,a + 2, which we know is b.b. Furthermore, the average of 55 consecutive numbers starting with bb is b+2=a+4.b + 2 = a + 4. Thus, B is the correct answer.
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Tagged: arithmetic sequence · mean

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