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2014 AMC 10A Problem 7

Problem 7 of 25EasierAlgebra

Nonzero real numbers x,x, y,y, a,a, and bb satisfy x<ax < a and y<b.y < b. How many of the following inequalities must be true? (I) x+y<a+bx + y \lt a + b (II) xy<abx - y \lt a - b (III) xy<abxy \lt ab (IV) xy<ab\dfrac{x}{y} \lt \dfrac{a}{b}

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Solution

Adding the two inequalities together gets us x+y<a+b, x + y \lt a + b, which shows that (I) is correct. One cannot subtract inequalities, which means that (II) is not necessarily true. Consider x=1,x = 1, y=1,y = 1, a=2,a = 2, and b=3b = 3 as a counter-example. This would give us 0<1.0 \lt -1. (III) is also not always true, since xx and yy might be negative numbers. Let x=3,x = -3, y=2,y = -2, a=1,a = 1, and b=1.b = 1. Then xy=6xy = 6 and ab=1ab = 1 which shows that (III) is wrong. The same thing occurs with (IV) . Using the same values as above, we have xy=1.5\dfrac{x}{y} = 1.5 and ab=1.\dfrac{a}{b} = 1. This shows that (I) is the only true statement. Thus, B is the correct answer.

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Concepts: inequality · counterexample

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