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2014 AMC 10A Problem 2

Problem 2 of 25EasierAlgebra

Roy’s cat eats 13\dfrac{1}{3} of a can of cat food every morning and 14\dfrac{1}{4} of a can of cat food every evening. Before feeding his cat on Monday morning, Roy opened a box containing 66 cans of cat food. On what day of the week did the cat finish eating all the cat food in the box?

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Solution

The cat eats 13+14=712 \dfrac{1}{3} + \dfrac{1}{4} = \dfrac{7}{12} cans of food each full day. After 1010 full days, it has eaten 10712=35610\cdot\frac7{12}=\frac{35}{6} cans, leaving 16\frac16 of a can. The cat finishes that remainder during its next morning feeding. The eleventh morning, counting Monday as the first, is Thursday. Thus, C is the correct answer.

More practice

Concepts: rate · fraction · date and time

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.