2020 AMC 10A Problem 1

Problem 1 of 25EasierAlgebra

What value of

x

satisfies

x- \frac{3}{4} = \frac{5}{12} - \frac{1}{3}?

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Solution

The right side is

\dfrac{5}{12}-\dfrac13=\dfrac{5}{12}-\dfrac4{12}=\dfrac1{12}

. Thus

x=\dfrac34+\dfrac1{12}=\dfrac9{12}+\dfrac1{12}=\dfrac56

. Thus, E is the correct answer.

Concepts: fraction · linear equation

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