Skip to main content

2020 AMC 10A Problem 19

Problem 19 of 25HarderCounting & Probability

As shown in the figure below, a regular dodecahedron (the polyhedron consisting of 1212 congruent regular pentagonal faces) floats in space with two horizontal faces. Note that there is a ring of five slanted faces adjacent to the top face, and a ring of five slanted faces adjacent to the bottom face. How many ways are there to move from the top face to the bottom face via a sequence of adjacent faces so that each face is visited at most once and moves are not permitted from the bottom ring to the top ring?

Answer choices

Show solution

Solution

After leaving the top face, choose one of the 55 top-ring faces. Because moves from the bottom ring to the top ring are forbidden, every valid path has a top-ring phase, then one move down to the bottom ring, then a bottom-ring phase. Fix the first top-ring face. On the top ring, the path can move around the 55-cycle without revisiting a face and then stop at any point: there are 1+24=91+2\cdot4=9 possible top-ring paths. From the stopping face, there are 22 possible downward moves to the bottom ring, so the top part has 1818 choices. Once in the bottom ring, the path can move around the bottom 55-cycle without revisiting a face and then enter the bottom face; this gives 1+24=91+2\cdot4=9 choices. The total is 5189=8105\cdot18\cdot9=810. Thus, E is the correct answer.

More practice

Concepts: graph theory · multiplication principle · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.