Skip to main content

2020 AMC 10A Problem 7

Problem 7 of 25EasierAlgebra

The 2525 integers from 10-10 to 14,14, inclusive, can be arranged to form a 55-by-55 square in which the sum of the numbers in each row, the sum of the numbers in each column, and the sum of the numbers along each of the main diagonals are all the same. What is the value of this common sum?

Answer choices

Show solution

Solution

The sum of the integers from 10-10 to 1414 is 2510+142=5025\cdot\dfrac{-10+14}{2}=50. If every row has common sum SS, then the five row sums add to 5050, so 5S=505S=50 and S=10S=10. Thus, C is the correct answer.

More practice

Concepts: magic square · arithmetic sequence

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.