2021 Fall AMC 10A Problem 1Problem 1 of 25·Easier·ArithmeticWhat is the value of the following expression? (2112−2021)2169\dfrac{(2112-2021)^2}{169}169(2112−2021)2Answer choicesA7771B2121212C4949493D6464644E9191915Submit answerStuck? Show hintsShow solutionSolutionSince 2112−2021=91=7⋅13,2112-2021=91=7\cdot13,2112−2021=91=7⋅13, (2112−2021)2169=(7⋅13)2132=72=49. \begin{aligned} \frac{(2112-2021)^2}{169} &=\frac{(7\cdot13)^2}{13^2}\\ &=7^2=49. \end{aligned} 169(2112−2021)2=132(7⋅13)2=72=49. Thus, C is the correct answer.AoPS wikiCopy problemTagged: fraction · exponent