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2021 Fall AMC 10A Problem 4

Problem 4 of 25EasierArithmetic

Mr. Lopez has a choice of two routes to get to work. Route A is 66 miles long, and his average speed along this route is 3030 miles per hour. Route B is 55 miles long, and his average speed along this route is 4040 miles per hour, except for a 12\dfrac{1}{2}-mile stretch in a school zone where his average speed is 2020 miles per hour. By how many minutes is Route B quicker than Route A?

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Solution

Mr. Lopez would take 630⋅60=12 \dfrac{6}{30} \cdot 60 = 12 minutes to travel on Route A. On Route B, he would take (5−0.540+0.520)⋅60=8.25 \left(\dfrac{5 - 0.5}{40} + \dfrac{0.5}{20}\right) \cdot 60 = 8.25 minutes. The difference in times along these routes is 12−8.25=3.7512 - 8.25 = 3.75 minutes. Thus, B is the correct answer.
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