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2021 Fall AMC 12A Problem 12

Problem 12 of 25IntermediateAlgebraNumber Theory

What is the number of terms with rational coefficients among the 10011001 terms in the expansion of (x23+y3)1000? \left(x\sqrt[3]{2} + y\sqrt{3}\right)^{1000}?

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Solution

The general term is (1000k)(x23)1000−k(y3)k,\binom{1000}{k}(x\sqrt[3]{2})^{1000-k}(y\sqrt{3})^{k}, whose coefficient contains 21000−k32^{\frac{1000-k}{3}} and 3k2.3^{\frac{k}{2}}. This is rational exactly when (1000−k)(1000 - k) is a multiple of 33 and kk is even. Since 1000≡1(mod3),1000 \equiv 1 \pmod 3, we need k≡1(mod3)k \equiv 1 \pmod 3 and kk even, which combine to k≡4(mod6).k \equiv 4 \pmod 6. The valid values k=4,10,…,1000k = 4, 10, \ldots, 1000 number 1000−46+1=167.\dfrac{1000 - 4}{6} + 1 = 167. Thus, the correct answer is C.
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Tagged: binomial theorem · divisibility

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