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2021 Fall AMC 12A Problem 16

Problem 16 of 25IntermediateAlgebraCounting & Probability

An organization has 3030 employees, 2020 of whom have a brand A computer while the other 1010 have a brand B computer. For security, the computers can only be connected to each other and only by cables. The cables can only connect a brand A computer to a brand B computer. Employees can communicate with each other if their computers are directly connected by a cable or by relaying messages through a series of connected computers. Initially, no computer is connected to any other. A technician arbitrarily selects one computer of each brand and installs a cable between them, provided there is not already a cable between that pair. The technician stops once every employee can communicate with each other. What is the maximum possible number of cables used?

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Solution

The technician keeps adding cables until the graph becomes connected. To maximize the count, keep the network disconnected for as long as possible: leave a single brand A computer isolated and fully connect the remaining 1919 brand A computers to all 1010 brand B computers. That uses 1910=19019 \cdot 10 = 190 cables while still disconnected. The next cable connects the last brand A computer, joining everyone, for a total of 190+1=191.190 + 1 = 191. Thus, the correct answer is B.

More practice

Concepts: graph theory · extremal argument

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.