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2021 Fall AMC 12A Problem 9

Problem 9 of 25EasierAlgebraGeometry

A right rectangular prism whose surface area and volume are numerically equal has edge lengths log2x,\log_2 x, log3x,\log_3 x, and log4x.\log_4 x. What is x?x?

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Solution

Let a=log2x,a = \log_2 x, b=log3x,b = \log_3 x, c=log4x.c = \log_4 x. Surface area equals volume gives 2(ab+bc+ca)=abc.2(ab + bc + ca) = abc. Dividing by abc,abc, 1=2(1c+1a+1b). 1 = 2\left(\frac{1}{c} + \frac{1}{a} + \frac{1}{b}\right). Since 1a=logx2,\dfrac{1}{a} = \log_x 2, etc., the sum is logx2+logx3+logx4=logx24.\log_x 2 + \log_x 3 + \log_x 4 = \log_x 24. Thus 1=2logx24,1 = 2\log_x 24, so logx24=12,\log_x 24 = \tfrac{1}{2}, meaning x12=24x^{\frac{1}{2}} = 24 and x=576.x = 576. Thus, the correct answer is E.

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Concepts: surface area · volume · logarithm

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.