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2021 Fall AMC 10B Problem 14

Problem 14 of 25IntermediateCounting & Probability

Una rolls 66 standard 66-sided dice simultaneously and calculates the product of the 66 numbers obtained. What is the probability that the product is divisible by 4?4?

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Solution

Count the complement, where the product is not divisible by 4.4. This happens if the product has no factor of 2,2, or exactly one factor of 2.2. All dice odd has probability (12)6=164.(\frac12)^6=\frac1{64}. Exactly one factor of 22 means exactly one die is 22 or 6,6, and the other five dice are odd. This has probability 626(12)5=464.6\cdot\frac26\cdot\left(\frac12\right)^5=\frac4{64}. The complement has probability 564,\frac5{64}, so the desired probability is 1564=5964.1-\frac5{64}=\frac{59}{64}. Thus, the answer is C .

More practice

Concepts: dice (probability) · complementary probability · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.