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2021 Fall AMC 10B Problem 3

Problem 3 of 25EasierAlgebra

The expression 2021202020202021\dfrac{2021}{2020} - \dfrac{2020}{2021} is equal to the fraction pq\frac{p}{q} in which pp and qq are positive integers whose greatest common divisor is 1.1. What is p?p?

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Solution

We can rewrite this as 20212021202020212020202020202021\dfrac{2021\cdot 2021}{2020\cdot 2021} -\dfrac{2020\cdot 2020}{2020\cdot 2021} =202122020220202021.= \dfrac{2021^2-2020^2}{2020\cdot 2021}. This can be simplified to (20212020)(2021+2020)20202021\dfrac{(2021-2020)(2021+2020)}{2020\cdot 2021} =404120202021.=\dfrac{4041}{2020\cdot 2021}. Since 40414041 is coprime with both 20202020 and 2021,2021, we know 40414041 is the numerator. Thus, the answer is E .

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Concepts: fraction · difference of squares

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.