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2021 Fall AMC 10B Problem 9

Problem 9 of 25EasierAlgebra

The knights in a certain kingdom come in two colors. 27\frac{2}{7} of them are red, and the rest are blue. Furthermore, 16\frac{1}{6} of the knights are magical, and the fraction of red knights who are magical is 22 times the fraction of blue knights who are magical. What fraction of red knights are magical?

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Solution

Let xx be the fraction of blue knights who are magical. Then the fraction of red knights who are magical is 2x.2x. The total magical fraction is a weighted average over the red and blue groups: 27(2x)+57(x)=16.\frac27(2x)+\frac57(x)=\frac16. Thus 97x=16,\frac97x=\frac16, so x=754.x=\frac7{54}. The red magical fraction is 2x=727.2x=\frac7{27}. Thus, the answer is C .

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Concepts: weighted mean · ratio and proportion · fraction · linear equation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.