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2021 Fall AMC 10B Problem 24

Problem 24 of 25HarderGeometryCounting & Probability

A cube is constructed from 44 white unit cubes and 44 blue unit cubes. How many different ways are there to construct the 2×2×22 \times 2 \times 2 cube using these smaller cubes? (Two constructions are considered the same if one can be rotated to match the other.)

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Solution

This is the number of ways to choose which 44 of the 88 cube vertices are blue, up to cube rotation. Use Burnside’s lemma on the 2424 rotations of the cube. The identity fixes (84)=70\binom84=70 colorings. The 66 quarter-turn face rotations each fix 2.2. The 33 half-turn face rotations each fix 6.6. The 88 rotations about opposite vertices each fix 4.4. The 66 half-turn rotations about opposite edges each fix 6.6. Thus the number of inequivalent constructions is 70+62+36+84+6624=7. \begin{gathered} \frac{70+6\cdot2+3\cdot6+8\cdot4+6\cdot6}{24}\\ =7. \end{gathered} Thus, the answer is A .

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Concepts: Burnside’s Lemma · cube geometry

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.