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2007 AMC 12B Problem 15

Problem 15 of 25IntermediateAlgebra

The geometric series a+ar+ar2+⋯a+ar+ar^2+\cdots has a sum of 7,7, and the terms involving odd powers of rr have a sum of 3.3. What is a+r?a+r?

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Solution

The odd-power terms are ar+ar3+⋯ar+ar^3+\cdots =r(a+ar2+⋯ ),=r(a+ar^2+\cdots), that is, rr times the even-power terms. The even-power terms sum to 7−3=4.7-3=4. So 3=4r,3=4r, giving r=34.r=\tfrac34. Then a=7(1−r)=74,a=7(1-r)=\tfrac74, and a+r=74+34=52. a+r=\dfrac74+\dfrac34=\dfrac52. Thus, the correct answer is E.
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